(3/2)^2-2x=(8/27)^x-2

Solution for (3/2)^2-2x=(8/27)^x-2 equation:

(3/2)^2-2x=(8/27)^x-2

We move all terms to the left:

(3/2)^2-2x-((8/27)^x-2)=0


Domain of the equation: 27)^x-2)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-2x-((+8/27)^x-2)+(+3/2)^2=0

We calculate fractions


-2x+()/27^x-2)*2)^2)+81^x/27^x-2)*2)^2)=0

We calculate fractions


-2x+(()*27^x)/729x^2+(-2)*2)^2)+81^x*27^x)/729x^2=0

We multiply all the terms by the denominator


-2x*729x^2+(()*27^x)+(-2)*2)^2)+81^x*27^x)=0


We calculate terms in parentheses: +(()*27^x), so:

()*27^x


Wy multiply elements

-1458x^3+(()*27^x)+(-2)*2)^2)+81^x*27^x)=0

We get rid of parentheses

-1458x^3+(()*27^x)-2)*2)^2)+81^x*27^x=0


We calculate terms in parentheses: +(()*27^x), so:

()*27^x


We do not support expression: x^3